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Question

The equation to the orthogonal trajectories of the system of parabolas y=ax2 is

A
x22+y2=c
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B
x2+y22=c
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C
x22y2=c
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D
x2y22=c
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Solution

The correct option is A x22+y2=c
Given the equation of the parabola is y=ax2......(1).
Now, differentiating both sides of (1) we get, dydx=2ax or, a=y2x.
Using this in equation (1) we get,
y=xy2......(2).
This is the differential equation corresponding to the parabola (1).
Now, the differential equation of the orthogonal trajectory of (1) is
y=x2y [ Replacing y in (2) by 1y]
or, 2y dy+xdx=0
Now integrating both sides we get,
y2+x22=c [ Where c is integrating constant]
This is the required equation of orthogonal trajectory to (1).

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