The equation2 cos2x-2sin2x-x2-1-x2-0-x-2 has

The correct option is D no solution RHS ≥ 2 LHS ≤ 2 equation holds only when LHS = RHS = 2 RHS = 2 gives x = 1 or 1 but this do ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Integration by Parts

The equation2...

Question

The equation
2 ${cos}^{2} (\frac{x}{2}) {sin}^{2} x = x^{2} + \frac{1}{x^{2}}, 0 \leq x \leq \frac{π}{2}$ has

one real solution

No worries! We‘ve got your back. Try BYJU‘S free classes today!

no solution

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Suggest Corrections

Similar questions

{cos}^{2} (\frac{x}{2}) {sin}^{2} x = x^{2} + \frac{1}{x^{2}}, 0 \leq x \leq \frac{π}{2}

2 {cos}^{2} \frac{π}{2} {sin}^{2} x = x^{2} + \frac{1}{x^{2}}, 0 \leq x \leq \frac{π}{2}

2 {cos}^{2} \frac{x}{2} {sin}^{2} x = x^{2} + \frac{1}{x^{2}}, 0 \leq x \leq \frac{π}{2}

\sqrt{1 + cos 2 x} = \sqrt{2} {sin}^{- 1} (sin x), - π \leq x \leq π,

\sqrt{1 + c o s 2 x} = \sqrt{2} s i n^{- 1} (s i n x), - π < x \leq π

Join BYJU'S Learning Program