Question

The equations of displacement of two waves are given as $Y_1=10\sin (\pi t+\pi /3)$ $Y_2=5(\sin 3\pi t+\sqrt{3}\cos 3\pi t$), then the ratio of their amplitude is

• A. $1:2$
• B. $2:1$
• C. $1:1$
• D. $3:1$

Answer 1

The correct option is C $1:1$

Amplitude of $Y_1=10\sin (m\pi t+\pi /3)$ is $A_1=10$

Ampltude of $Y_2=10(\frac{1}{2}\sin 3\pi t+\frac{\sqrt{3}}{2}\cos 3\pi t)=10\sin (3\pi t+\pi /3)$ is $A_2=10$

$\frac{A_1}{A_2}=1:1$