The equations $x = t^{3} + 9$ and $y = \frac{3 t^{3}}{4} + 6$ represents a straight line where $t$ is a parameter. The $y$ intercept of the line is

- \frac{3}{4}

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Solution

The correct option is A $- \frac{3}{4}$
$x = t^{3} + 9$
$\Rightarrow t^{3} = x - 9$
$y = \frac{3 t^{3}}{4} + 6$
$\Rightarrow y = \frac{3}{4} (x - 9) + 6$
For y-intercept , put $x = 0$
$\Rightarrow y = - \frac{3}{4}$

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