The equilibrium constant at 25∘C for the reaction Fe2++Ag+⇌Fe3++Ag is:
Given E0Ag+/Ag=0.7998VandE0Fe3+/Fe2+=0.771V, log 2 =0.30, log 3 = 0.48, 2.303RTF=0.06
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Solution
At equilibrium E(Cell)=0
According to Nernst equation, E(Cell)=E0(Cell)−2.303RTnFlogQc 0=(0.7998−0.771)−0.061logKc So, logKc=0.48⇒Kc=3