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Standard XII

Chemistry

Derivation of Kp and Kc

The equilibri...

Question

The equilibrium constant at 298, K for a reaction $A + B ⇌ C + D$ is 100. If the initial concentration of all the four species were 1 M each, then equilibrium concentration of D (in mol $L^{- 1}$ ) will be:

0.818

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1.818

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1.182

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0.182

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Solution

The correct option is B 1.818
A + B $⇌$ C + D
t = 0 1 1 1
at eq 1-x 1+x 1+x

$\Rightarrow \frac{(1 + x)^{2}}{(1 - x)^{2}} = 100 \Rightarrow \frac{(1 + x)}{(1 - x)} = 10$
$\Rightarrow 1 + x = 10 - 10 x 11 x = 9$
$\Rightarrow x = \frac{9}{11}$
$\Rightarrow [D] = 1 + \frac{9}{11}$
$\Rightarrow$ [D] = 1.818

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Similar questions

Q. The equilibrium constants at

298 K

for a reaction

A + B ⇌ C + D

is 100. If the initial concentration of all the four species were

1 M

each then equilibrium concentration of

D ({in mol L}^{- 1})

will be:

The equilibrium constant at 298 K for a reaction $A + B ⇌ C + D$ is 100. If the initial concentration of all the four species were 1 M each, then equilibrium concentration of D (in mol $L^{- 1}$ ) will be:

Q. The equilibrium constant at

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. If the initial concentration of all the four species were

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Q. The equilibrium constants at

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A + B ⇌ C + D

is 100. If the initial concentration of all the four species were

1 M

each then equilibrium concentration of

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will be:

Q. The equilibrium constant at 298 K for a reaction

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is 100. If the initial concentration of all the four species were 1 M each, then equilibrium concentration of

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The equilibrium constant at 298, K for a reaction A+B⇌C+D is 100. If the initial concentration of all the four species were 1 M each, then equilibrium concentration of D (in mol L−1 ) will be:

The correct option is B 1.818 A + B ⇌ C + D t = 0 1 1 1 at eq 1-x 1+x 1+x ⇒ (1+x)2(1−x)2=100 ⇒ (1+x)(1−x)=10 ⇒ 1+x=10−10x 11x=9 ⇒ x=911 ⇒ [D]=1+911 ⇒ [D] = 1.818

The equilibrium constant at 298, K for a reaction $A + B ⇌ C + D$ is 100. If the initial concentration of all the four species were 1 M each, then equilibrium concentration of D (in mol $L^{- 1}$ ) will be: