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Question

The equilibrium constant for the reaction 2SO2 + O2 2 SO3 is 900 atm1 at 800K. A mixture containing SO3 and O2 having initial pressures of 1atm and 2atm is heated to equilibrate. The partial pressure of O2at equilibrium will be

A
0.97atm
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B
0.012atm
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C
2.01atm
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D
0.024atm
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Solution

The correct option is C 2.01atm
Correct option is c). Considering the backward reaction we have,
2SO32SO2+O2KP=1/900 atmInitial pressure1 atm02 atmPressure at equilibrium1xx2+x/2

Let partial pressure of SO2= p1and partial pressure of O2= p2and partial pressure of SO3=p3
K<p = (p1)2× (p2)/ (p3)2=x2 (2+x/2)/ (1x)2=1/900
AsKpfor this reaction is very small, x << 1.
Taking 2+x/2 as x and (1x) as x and solving for x, we get
X = 0.0236
Hence, at equilibrium, partial pressure of SO3= 1X=0.9764atm,
Partial pressure of SO2= x = 0.0236atm
And Partial pressure of O2= 2+x/2=2.0118atm


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