The equilibrium constant for the reaction N2(g)+O2(g)=2NO(g)at temperature T is 4×10−4. The value of Kc for the reaction:
NO(g)=12N2(g)+12O2(g) at the same temperature is :
A
2.5×102
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
50
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
4×10−4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.02
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A50 The equilibrium constant for the
reaction N2(g)+O2(g)=2NO(g)at temperature T is 4×10−4. The value of Kc for the reaction: NO(g)
=12N2(g)+12O2(g)
at the same temperature is 1√Kc=1√4×10−4=50 Note: The second reaction is obtained when the first reaction is reversed and divided by 2.