The equilibrium constant for the reaction will be:Cu(s)+Cu2+(aq.)⇌2Cu+(aq.)E∘Cu2+/Cu=0.34 V E∘Cu2+/Cu+=0.15 V(Given: log3.72=0.571)
Given the half cell reactions: Cu+(aq)+e−→Cu(s);E0=+0.52 VCu2+(aq)+e−→Cu+(aq);E0=+0.165 V The equilibrium constant for the disproportionation reaction at 298 K is: 2Cu+(aq)→Cu(s)+Cu2+(aq)