The equilibrium constant $K_{c}$ for the reaction $N_{2 (g)} + 3 H_{2} ⇌ {2 N H}_{3 (g)}$ is $0.286$ at $500^{o} C$ . Calculate $K_{c}$ and $K_{p}$ for the reaction $2 N H_{3 (g)} ⇌ N_{2 (g)} + {3 H}_{2 (g)}$ .

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Solution

$2 {N H}_{3} ⇌ N_{2} (g) + 3 H_{2} (g)$
$K_{C} = \frac{[N_{2}] {[H_{2}]}^{3}}{{[{N H}_{3}]}^{2}} K_{P} = \frac{{P N}_{2} . {P H}_{2}^{3}}{{P N H}_{3}^{2}}$

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