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Question

The equilibrium constant kp for the reaction
2SO2+O22SO3 is 2.5 atm1 . What would be the partial pressure of O2, if the equilibrium pressures of SO2 and SO3 are equal?

A
304 mm
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B
30.4 mm
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C
0.04 mm
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D
760 mm
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Solution

The correct option is A 304 mm
The equilibrium reaction is 2SO2+O22SO3
The expression for the equilibrium constant is Kp=[SO3]2[SO2]2[O2]
But [SO3]=[SO2] and Kp=2.5atm1
Substitute the values in the above expression.
2.5=[SO3]2[SO2]2[O2]=1[O2]
Thus [O2]=0.4=0.4×760=304mm

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