The equilibrium constant of the reaction
SO2(g)+12O2(g)⇋SO_3_{(g)}~is~4 \times 10^{-3}atm .The equilibrium constant of the reaction 2SO_3_(g)⇋2SO_2_{(g)}+O_2(g)\) would be :
6.25 × 104atm2
SO2(g)+12O2(g)⇌SO3(g);K1=4×10−3atm−12
2SO3(g)⇌2SO2(g)+O2(g);K2=1(K1)2
K2=1(4×10−3)2=6.25×104 atm2