The equilibrium constants for the following are: N2+3H2⇌2NH3K1 N2+O2⇌2NOK2 H2+12O2→H2OK3
The equilibrium constant (K) of the reaction: 2NH3+52O2K⇌2NO+3H2O, will be
A
K1K33/K2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
K2K33/K1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
K2K3/K1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
K32K3/K1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is BK2K33/K1 (I)N2+3H2⇌2NH3;K1=[NH3]2[N2][H2]3(II)N2+O2⇌2NO;K2=[NO]2[N2][O2](III)H2+12O2⟶H2O;K3=[H2O][O2]12 (II+3×III–II) will give 2NH3+52O2K⇌2NO+3H2O ∴K=K2×K33/K1