The equilibrium mixture for 2SO2(g)+O2(g)⇌2SO3(g) present in 1L vessel at 600oC contains 0.50, 0.12, and 5.0 mole of SO2,O2andSO3 respectively.
Calculate KC for the given change at 600oC.
A
675.23mol−1L
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B
765.32mol−1L
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C
833.33mol−1L
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D
801.23mol−1L
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Solution
The correct option is C833.33mol−1L The equilibrium reaction is 2SO2(g)+O2(g)⇌2SO3(g).
The expression for the equilibrium constant, Kc=[SO3]2[SO2]2[O2]
Substituting given values in the above expression, we get, Kc=(5)2(0.5)2×0.12=833.33mol−1L