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Question

The equilibrium of formation of phosgene is represented as:
CO(g)+Cl2(g)COCl2(g)
The reaction is carried out in a 500mL flask. At equilibrium 0.3 mole of phosgene, 0.1 mole of CO and 0.1 mole of Cl2 are present. The equilibrium constant of the reaction is_________.

A
30
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B
15
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C
5
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D
3
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Solution

The correct option is B 15
The equilibrium of formation of phosgene is represented as:
CO(g)+Cl2(g)COCl2(g)
The reaction is carried out in a 500mL flask. At equilibrium 0.3 mole of phosgene, 0.1 mole of CO and 0.1 mole of Cl2 are present.
[COCl2]=0.3mol500mL×1000mL/L=0.6M
[CO]=[Cl2]=0.1mol500mL×1000mL/L=0.2M
The equilibrium constant of the reaction is
Kc=[COCl2][CO][Cl2]
Kc=0.60.2×0.2
Kc=15

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