Question

The equilibrium $P_4\left(s\right)+6C{l}_2\left(g\right)\leftrightharpoons 4PC{l}_3\left(g\right)$ Is attained by mixing equal moles of $P_{4}andC{l}_2$ inana evacuated vessel. Then at equilibrium

• A. $\left[C{l}_2\right]>\left[PC{l}_3\right]$
• B. $\left[C{l}_2\right]>\left[P_4\right]$
• C. $\left[P_4\right]>\left[C{l}_2\right]$
• D. $\left[PC{l}_3\right]>\left[P_4\right]$

Answer 1

The correct option is C $\left[P_4\right]>\left[C{l}_2\right]$

Solution:Correct option is c).

$\begin{array}{cccc}& P_4\left(s\right)+& 6C{l}_2\left(g\right)\leftrightharpoons & 4PC{l}_3\left(g\right)\\ Initialmoles& 1& 1& 0\\ Atequilibrium& 1-x& 1-6x& 4x\end{array}$

$As(1-x)>(1-6x),Hence\left[P_4\right]>\left[C{l}_2\right].$