The equilibrium vapour pressure of water vapour over a 0-20 mole sample of liquid water is 35 torr at 27- C- If the amount of the liquid water is decreased to 0-10 mole- the equilibrium vapour pressure of it would beA- 17-5 torrB- 51-5 torrC- None of theseD- 35-0 torr

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Vapour Pressure

The equilibri...

Question

The equilibrium vapour pressure of water vapour over a 0.20 mole sample of liquid water is 35 torr at $27^{\circ} C$ . If the amount of the liquid water is decreased to 0.10 mole, the equilibrium vapour pressure of it would be

17.5 torr

No worries! We‘ve got your back. Try BYJU‘S free classes today!

35.0 torr

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

51.5 torr

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 35.0 torr
The equilibrium vapour pressure will remain the same. It is independent of the quantity or the amount of substance. It depends only on temperature.

Suggest Corrections

Similar questions

Q. The equilibrium vapour pressure of water vapour over a 0.20 mole sample of liquid water is 35 torr at

27^{\circ} C

. If the amount of the liquid water is decreased to 0.10 mole, the equilibrium vapour pressure of it would be

Q. The vapour pressure of pure liquid is

70

Torr at

27^{o} C

. The vapour pressure of a solution of this liquid and another liquid (mole fraction 0.2) is

84

Torr at

27^{o} C

. The vapour pressure of pure liquid

B

27^{o} C

is?

Q. The vapour pressure of two liquids P and Q are 80 and 60 torr respectively. The total vapour pressure of solution obtained by mixing 3 mole of P and 2 mol of Q would be

Q. Two completely miscible liquids A and B form an ideal solution. What is the vapour pressure of a solution containing 2 moles of A and 3 moles of B at 300 K?
Given: At 300 K, Vapour pressure of pure liquid A (

P_{A}^{0}

) = 100 torr
Vapour pressure of pure liquid B (

P_{B}^{0}

) = 300 torr

Q. The vapour pressure of a pure liquid

A

70

torr at

27^{0} C

. It forms an ideal solution with another liquid B. The mole fraction of B is

0.2

and the total vapour pressure of the solution is

84

torr at

27^{0} C

. The vapour pressure of pure liquid

B

27^{0} C

is:

Join BYJU'S Learning Program

Explore more

Vapour Pressure

Standard XII Chemistry

Join BYJU'S Learning Program

The equilibrium vapour pressure of water vapour over a 0.20 mole sample of liquid water is 35 torr at 27∘ C. If the amount of the liquid water is decreased to 0.10 mole, the equilibrium vapour pressure of it would be

The correct option is B 35.0 torrThe equilibrium vapour pressure will remain the same. It is independent of the quantity or the amount of substance. It depends only on temperature.

The equilibrium vapour pressure of water vapour over a 0.20 mole sample of liquid water is 35 torr at $27^{\circ} C$ . If the amount of the liquid water is decreased to 0.10 mole, the equilibrium vapour pressure of it would be

The correct option is B 35.0 torr
The equilibrium vapour pressure will remain the same. It is independent of the quantity or the amount of substance. It depends only on temperature.