Question

The equivalent conductivity of a solution containing 2.54g of $CuS{O}_4$ per litre is $91.0{\Omega }^{-1}c{m}^{2}e{q}^{-1}$. Its conductivity would be :

• A. $2.9\times {10}^{-3}{\Omega }^{-1}c{m}^{-1}$
• B. $1.8\times {10}^{-2}{\Omega }^{-1}c{m}^{-1}$
• C. $2.4\times {10}^{-4}{\Omega }^{-1}c{m}^{-1}$
• D. $3.6\times {10}^{-3}{\Omega }^{-1}c{m}^{-1}$

Answer 1

The correct option is A $2.9\times {10}^{-3}{\Omega }^{-1}c{m}^{-1}$

We know that,
$k=\frac{{\Lambda }_{eq}\times C}{1000}$

Given, ${\Lambda }_{eq}=91.0{\Omega }^{-1}c{m}^{2}e{q}^{-1}$

Now,

$k=\left(91{\Omega }^{-1}c{m}^{2}e{q}^{-1}\right)(\frac{2.54\times 2}{159\times 1000}eq.c{m}^{-3})$

$k=2.9\times {10}^{-3}{\Omega }^{-1}c{m}^{-1}$