The equivalent inductance seen at terminals $A - B$ in figure is ---------- $H$

8

Open in App

Solution

The correct option is A 8

$L = L_{1} + L_{2} + L_{3} - 2 M_{12} + 2 M_{23} - 2 M_{13}$

$= 4 + 4 + 4 - (2 \times 2) + (2 \times 1) - (2 \times 1)$

$= 8 H$

Suggest Corrections

Similar questions

In the circuit shown in the figure, the angular frequancy $ω$ (in rad/s), at which the Norton equivalent impendance as seen from terminals b-b' is purely resistive, is

Q. The equivalent resistance seen across the terminal A' and 'B in the figure given below is

Q. Consider the circuit shown in the figure below;
The Norton's equivalent seen across the terminal A and B is

Q. In the network shown below, remove terminal C and obtain the Norton equivalent seen at terminals a and b.

Q. In the circuit of Fig. the equivalent impedance seen across terminals A, B is

Join BYJU'S Learning Program

The equivalent inductance seen at terminals A−B in figure is ----------H 8

The correct option is A 8 L=L1+L2+L3−2M12+2M23−2M13 =4+4+4−(2×2)+(2×1)−(2×1) =8H

The equivalent inductance seen at terminals $A - B$ in figure is ---------- $H$

8

The correct option is A 8

$L = L_{1} + L_{2} + L_{3} - 2 M_{12} + 2 M_{23} - 2 M_{13}$

$= 4 + 4 + 4 - (2 \times 2) + (2 \times 1) - (2 \times 1)$

$= 8 H$