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Ion Electron Method

The equivalen...

Question

The equivalent mass of $K I O_{3}$ during its reaction with ascorbic acid in presence of $5 M H C l$ is :

35.66

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53.5

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42.8

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107

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Solution

The correct option is D 53.5
The balanced redox equation is $C_{6} H_{8} O_{6} + I O_{3}^{-} + H^{+} + C l^{-} ⇌ C_{6} H_{6} O_{6} + I C l + 2 H_{2} O$
The oxidation number of iodine changes from +5 to +1.
The change in the oxidation number is 4.
The molar mass of $K I O_{3}$ is $39.1 + 126.9 + 3 (16) = 214 g / m o l$
The equivalent mass of $K I O_{3}$ is $\frac{Molar mass}{Change in the oxidation number} = \frac{214}{4} = 53.5$

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