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The equivalen...

Question

The equivalent mass of $N_{2} H_{4}$ in the change, $N_{2} H_{4} ⟶ N_{2}$ is:

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Solution

$N_{2} H_{4} ⟶ N_{2}$
-2 0
As we know,
Equivalent weight $= \frac{m o l a r w t .}{n - f a c t o r} = \frac{M}{4} = \frac{32}{4} = 8$ .

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