The equivalent mass of sodium thiosulphate (Na2S2O3⋅5H2O) in the reaction,
2Na2S2O3+I2→2NaI+Na2S4O6 is
The equivalent weight is the gram molecular weight divided by the number of electrons lost or gained by each molecule; For sodium thiosulfate (Na2S2O3⋅5H2O), this is (248.17/1) g.
In case of Sodium Thiosulfate the reaction proceeds as under:
I2+2Na2S2O3→Na2S4O6+2NaI
The conversion of 2Na2S2O3 to I2 2 electrons are transfered.
Hence for 1 Na2S2O3, 1 electron is transfered.
Thus Molecular weight divded by 1 is the equivalent weight & hence both have same value.
Hence option A is correct.