The equivalent resistance between (a) & (b) in the circuit can be obtained by the expression:

$\frac{1}{R_{e q}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} + \frac{1}{R_{4}}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$\frac{1}{R_{e q}} = \frac{1}{R_{1}} - \frac{1}{R_{2}} - \frac{1}{R_{3}} - \frac{1}{R_{4}}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$R_{e q} = R_{1} + R_{2} + R_{3} + R_{4}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$R_{e q} = R_{1} - R_{2} - R_{3} - R_{4}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$\frac{1}{R_{e q}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} + \frac{1}{R_{4}}$

In a parallel circuit, the voltage across each of the components is the same.
For parallel connection,
$\frac{1}{R_{e q}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} + . . . + \frac{1}{R_{n}}$ .
$∴$ Equivalent resistance between (a) & (b) is obtained by the expression, $\frac{1}{R_{e q}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} + \frac{1}{R_{4}}$ .

Suggest Corrections