Question

The equivalent resistance between points A and B in the circuit shown is

• A. $4\Omega$
• B. $6\Omega$
• C. $10\Omega$
• D. $8\Omega$

Answer 1

The correct option is C $10\Omega$

By applying $\frac{1}{R_p}=\frac{1}{R_1}+\frac{1}{R_2}+...$ and $R_s=R_1+R_2+...$ we can reduce the circuit to a series combination of $4\Omega ,4\Omega \text{and}2\Omega$ which gives the equivalent resistance as $10\Omega$.