The equivalent resistance of a circuit that has two equal resistors in series is $8 Ω$ . Find the value of each resistor.

$8 Ω$

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$2 Ω$

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$4 Ω$

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$1 Ω$

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Solution

The correct option is C
$4 Ω$

Since the resistors $R_{1}$ & $R_{2}$ are in series, the effective resistance of the circuit is given by:
$R_{e f f}$ = $R_{1}$ + $R_{2}$
Given: $R_{1}$ & $R_{2}$ are equal, $R_{1}$ = $R_{2} = R$
$∴ R_{e f f} = R + R = 8 Ω$
$\Rightarrow 2 R = 8 Ω$ $\Rightarrow R = 4 Ω$

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The equivalent resistance of a circuit that has two equal resistors in series is 8 Ω. Find the value of each resistor.

The correct option is C 4 Ω Since the resistors R1 &R2 are in series, the effective resistance of the circuit is given by: Reff =R1 +R2 Given: R1 &R2 are equal, R1 = R2=R ∴Reff=R+R=8Ω ⇒2R=8Ω⇒R=4Ω

The equivalent resistance of a circuit that has two equal resistors in series is $8 Ω$ . Find the value of each resistor.