The equivalent weight of ${C u}_{2} S$ $(m o l . w t . = M)$ in the following reaction is:
${C u}_{2} S + 4 {M n O}_{4} ⟶ {C u}^{2} + {S O}_{2} + {M n}^{2 +}$

M / 2

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M / 6

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M / 8

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M / 4

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Solution

The correct option is B $M / 6$
In this reaction copper $+ 1$ to copper $+ 2$
And sulphur $- 2$ to sulphur $+ 4$
Total number of ions exchange in this reaction=(2-1)+(4-(-1))=6
Equivalent weight= Molecular weight/n factor
n factor is equal to number of ions change in a reaction.
So
equivalent weight=M/6

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