Question

The equivalent weight of $HN{O}_3$ (molecular weight =$63$) in the following reaction is:

$3Cu+8HN{O}_3\to 3Cu(N{O}_3{)}_2+2NO+4H_{2}O$

• A. $\frac{4\times 63}{3}$
• B. $\frac{63}{5}$
• C. $\frac{63}{3}$
• D. $\frac{63}{8}$

Answer 1

Answer: (A)

$\frac{4\times 63}{3}$

The reaction is

$3Cu+\underset{+5}{8{HNO}_3}⟶3Cu{\left({NO}_3\right)}_2+\underset{+2}{2NO}+4H_{2}O$

change in electrons $=3$

molecular weight $=63$

Equivalent weight $=\frac{4\times 63}{3}$

Ans :- Option A.