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Question

The equivalent weight of hypo in the reaction [M = Molecular Weight]
2Na2S2O3+I22NaI+Na2S4O6 is

A
M
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B
M2
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C
M3
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D
M4
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Solution

The correct option is B M

Equivalent Weight =Mnfactor

2Na2S2O3+I22NaI+Na2S4O6

Oxidation state of S
in S2O232x6=2

Oxidation state of S
in S4O264x12=2; x=2.5

Na2S2O3 n factor=2(2.52)=2×12=1

Equivalent weight =M1=M


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