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Potassium Dichromate

The equivalen...

Question

The equivalent weight of $N a H C_{2} O_{4}$ when it behaves as an acid is equal to:

Molecular weight

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\frac{Molecular weight}{3}

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\frac{Molecular weight}{2}

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none of the above

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Solution

The correct option is A $Molecular weight$
$N a H C_{2} O_{4}$ has one ionisable $H^{+}$ and thus, its equivalent weight $=$ its molecular weight.
$N a H C_{2} O_{4} ⇌ {N a}^{+} + H C_{2} O_{4}^{-} ⇌ H^{+} + C_{2} O_{4}^{-}$

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y

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