The equivalent weight of underlined compound is $(90 + x)$ Find the value of $x$ _________.
$2 C_{6} H_{5} O H - --------- - + 2 N a ⟶ 2 C_{6} H_{5} N a + H_{2}$

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Solution

In the given reaction, 1 mole of phenol reacts with one mole of sodium.
Hence, its equivalent weight will be equal to its molecular weight.
Equivalent weight of $C_{6} H_{5} O H = \frac{m o l e c u l a r w e i g h t .}{1} = \frac{94}{1} = 94$

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