The example of cyclic silicate is.

B e_{3} A l_{2} [S i_{6} O_{18}]

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A l_{2} (O H)_{4} S i_{2} O_{5}

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(N a_{g} [A l_{6} S i_{6} O_{24}] S_{2})

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Z n_{2} (S i O_{4})

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Solution

The correct option is A $B e_{3} A l_{2} [S i_{6} O_{18}]$
Cyclic silicates have general formula: $[S i O_{3}]_{n}^{2 n -}$

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[S i_{6} O_{18}]^{n -}

[S i_{6} O_{18}]^{n -}

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