Question

The excess pressure inside a soap bubble is twice the excess pressure inside a second soap bubble. The volume of the first bubble is n times the volume of the second where n is:

• A. $0.125$
• B. $2$
• C. $1$
• D. 0.037

Answer 1

The correct option is A $0.125$

$\frac{Volumeoffirstbubble}{Volumeofsecondbubble}=\eta \frac{r_1}{r_2}={\eta }^{1/3}\frac{P_1}{P_2}=\frac{r_2}{r_1}=2{\eta }^{1/3}=\frac{1}{2}\eta =\frac{1}{8}=0.125$