Question

The excess pressure of one soap bubble is four times more than other. Than the ratio of volume of the first bubble to another is

• A. 1 : 64
• B. 1 : 4
• C. 64 : 1
• D. 1 : 2

Answer 1

The correct option is A

1 : 64

$\frac{P_1}{P_2}=4or{P}_1=4P_2$
$\frac{4s}{r_1}=\frac{4\times 4s}{r_2}or\frac{r_1}{r_2}=\frac{1}{4}$
$\frac{v_1}{v_2}=\frac{r_1^3}{r_2^3}=(\frac{1}{4}{)}^3=\frac{1}{64}$