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Question

The expansion of (x+y)3 is x3+y3+3x2y−3xy2


A

x3 + y3 + 3x2y - 3xy2

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B

x3 + y3 - 3x2y + 3xy2

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Solution

The correct option is B

x3 + y3 - 3x2y + 3xy2


(x+y)3=(x+y)(x+y)2
=(x+y)(x2+2xy+y2)

(x+y)3=x(x2+2xy+y2)+y(x2+2xy+y2)
=x3+2x2y+xy2+x2y+2xy2+y3

=x3+y3+3x2y+3xy2

So, The given statement is false.


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