The exponent of 2 in the prime factorisation of 144, is

(a) 4
(b) 5
(c) 6
(d) 3

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Solution

Using the factor tree for prime factorization, we have:

Therefore,

Thus, the exponent of 2 in 144 is 4.

Hence the correct choice is (a).

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Similar questions

If the prime factorisation of a and b are

$a = 2^{2} \times 3 \times x$

$b = 2 \times 3^{2} \times y$ and

LCM of (a, b) = $2^{2} \times 3^{2} \times 5^{2}$ and

HCF of (a, b) = $2 \times 3 \times 5$ , which of the following is true? ( $x \neq 1, y \neq 1$ )

a = 2^{2} \times 3 \times x

b = 2 \times 3^{2} \times y

2^{2} \times 3^{2} \times 5^{2}

2 \times 3 \times 5

x \neq 1, y \neq 1

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