Question

The exponential form of $\sqrt{\sqrt{2}+\sqrt{3}}$ is:

• A. $6$
• B. $(6{)}^{\frac{1}{2}}$
• C. $(6{)}^{\frac{1}{4}}$
• D. $(6{)}^{\frac{-1}{2}}$

Answer 1

The correct option is C $(6{)}^{\frac{1}{4}}$

$\sqrt{\sqrt{2}\times \sqrt{3}}=\sqrt{\sqrt{6}}=6^{\frac{1}{4}}$