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Question

The expression (2x−5y)2 is equal to

A
4x220xy25y2
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B
4x220xy+15y2
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C
4x220xy+25y2
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D
4x210xy+25y2
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Solution

The correct option is C 4x220xy+25y2
Concept Involved––––––––––––––––––:
(ab)2=a22ab+b2

Method–––––––:
Using the FOIL rule.
F=First term, O= Outside term, I = Inside term, L= Last term.

(2x5y)2=(2x5y)(2x5y)
=(2x)(2x5y)+(5y)(2x5y)
=(2x)(2x)(2x)(5y)+(5y)(2x)+(5y)(5y)
=(2x)2+2(2x)(5y)+(5y)2
=4x2+2(2x)(5y)+25y2
=4x220xy+25y2

This is the required expression obtained using FOIL rule.
Also, we can use the identity
(ab)2=a22ab+b2.

(2x5y)2
=(2x)2+2(2x)(5y)+(5y)2
=4x2+2(2x)(5y)+25y2
=4x220xy+25y2

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