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Characteristics of Equilibrium Constant

The expressio...

Question

The expression for equilibrium constant, $K_{c}$ for the following reaction is :
$F e_{(}^{3 +} a q) + 3 O H_{(}^{-} a q) ⇌ F e (O H)_{3 (s)}$

K_{c} = \frac{[F e (O H_{3})]}{[F e^{3 +}] [O H^{-}]^{3}}

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K_{c} = \frac{[F e (O H_{3})]}{[F e^{3 +}] [O H^{-}]}

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K_{c} = \frac{1}{[F e^{3 +}] [O H^{-}]^{3}}

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K_{c} = [F e (O H_{3})]

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Solution

The correct option is D $K_{c} = \frac{1}{[F e^{3 +}] [O H^{-}]^{3}}$
$F e^{3 +} (a q) + 3 O H^{-} (a q) ⇌ F e (O H)_{3} (s)$
Since the concentration of solids = 1, the expression of
$K_{c} = \frac{1}{[F e^{3 +}] [O H^{-}]^{3}}$

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I_{2 (s)} + 5 F_{2} (g) \to 2 I F_{5} (g)

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