The expression for the solubility product of ${A g}_{2} {C O}_{3}$ will be:

K_{s p} = s^{2}

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K_{s p} = {4 s}^{3}

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K_{s p} = {27 s}^{4}

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K_{s p} = s

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Solution

The correct option is C $K_{s p} = {4 s}^{3}$
In aqueous solution, silver carbonate dissociates as follows:

${A g}_{2} C O_{3} ⟶ 2 {A g}^{+} + C O_{3}^{2 -}$

Let the solubility be $s$ .

The solubility of silver will be $2 s$ as two moles ions are dissociated.

$K_{s p} = {[{A g}^{+}]}^{2} [{C O_{3}}^{-}]$

$K_{s p} = (2 s)^{2} \times s = 4 s^{3}$

So, the correct option is $B$

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