Question

The expression $(\frac{1}{\sqrt{2}}\hat{i}+\frac{1}{\sqrt{2}}\hat{j})$ is a

• A. Unit vector
• B. Null vector
• C. Vector of magnitude
• D. $\sqrt{2}$

Answer 1

The correct option is A

Unit vector

$\overrightarrow{P}=\frac{1}{\sqrt{2}}\hat{i}+\frac{1}{\sqrt{2}}\hat{j}\therefore |\overrightarrow{P}|=\sqrt{{\left(\frac{1}{2}\right)}^2+{\left(\frac{1}{2}\right)}^2}=1$
$\therefore$ It is a unit vector.