The extent of charge of lead accumulator is determined by:

amount of

P b {S O}_{4}

in the battery

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amount of

P b O_{2}

in the battery

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specific gravity of

H_{2} {S O}_{4}

of the battery

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amount of

P b

in the battery

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Solution

The correct option is C specific gravity of $H_{2} {S O}_{4}$ of the battery
The extent of charge of a lead accumulator is determined by the specific gravity of $H_{2} {S O}_{4}$ of the battery.
Note: The density of the fully charged lead accumulator is 1.30 g/ml and when it drops below 1.20 g/ml, the lead accumulator needs recharging.

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Similar questions

Identify the monoatomic and polyatomic ions from the following equation-
$P b (N O_{3})_{2}$ + $K_{2} S O_{4}$ $\to$ $2 K N O_{3}$ + $P b S O_{4}$

P b S O_{4} + 2 e \to P b + S O_{4}^{2 -}

P b S O_{4} + 2 H_{2} O \to P b O_{2} + S O_{4}^{2 -} + 4 H + 2 e

H_{2} 3 O_{4}

P b (s) + P b O_{2} + 2 H_{2} S O_{4} (a q) \to 2 P b S O_{4} (s) + 2 H_{2} O

1.25 A

H_{2} S O_{4}

P b {S O}_{4}

0.01 M

{N a}_{2} {S O}_{4}

K_{s p}

P b {S O}_{4} = 1.25 \times 10^{- 9}

Calculate the percentage composition of oxygen in lead nitrate [Pb(NO₃)₂].
(Pb = 207, N = 14, O = 16)

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