Question

The external and internal diameters of a hollow cylinder are measured to be (4.23 $\pm$ 0.01) cm and (3.89 $\pm$ 0.01)cm. The thickness of the wall of the cylinder is

• A. $(0.34\pm 0.02)cm$
• B. $(0.17\pm 0.02)cm$
• C. $(0.17\pm 0.01)cm$
• D. $(0.34\pm 0.01)cm$

Answer 1

The correct option is C

$(0.17\pm 0.01)cm$

$t=\frac{d_2-d_1}{2}t=0.17cm\Delta t=\pm \frac{\Delta d_2}{2}\pm \frac{\Delta d_1}{2}\Delta t=\pm 0.01cm$