Question

The faces of a die bear numbers $0,1,2,3,4,5$ if the die is rolled twice, then find the probability that the product of digits on the upper face is zero.

Answer 1

We have,

probability of products

$0\times 0$

$0\times 1$

$0\times 2$

$0\times 3$

$0\times 4$

$0\times 5$

$1\times 0$

$1\times 1$…..

So we can make out that events would be $6\times 6=36$

Number of time $6+5=11$

So have probability$=\frac{11}{36}$

Hence, this is answer.