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Byju's Answer
Standard VIII
Mathematics
Common Factors/ HCF
The factorisa...
Question
The factorisation of
3
a
5
−
108
a
3
is equal to
A
3
a
3
(
a
+
6
)
(
a
+
6
)
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B
3
a
3
(
a
−
6
)
(
a
+
6
)
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C
3
a
2
(
a
−
6
)
(
a
−
6
)
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D
3
a
3
(
a
−
6
)
(
a
+
6
)
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Solution
The correct option is
B
3
a
3
(
a
−
6
)
(
a
+
6
)
The given expression is
3
a
5
−
108
a
3
Taking out
3
a
3
we get
3
a
3
(
a
2
−
36
)
=
3
a
3
(
a
2
−
6
2
)
=
3
a
3
(
a
−
6
)
(
a
+
6
)
Suggest Corrections
0
Similar questions
Q.
Factorise
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−
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Q.
Tick (✓) the correct answer:
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