The factors of quadratic polynomial $P (x) = x^{2} + 4 x - 5$ are ................

(x + 5) (x - 1)

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(x + 5) (x + 1)

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(x + 1) (x - 5)

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(x - 1) (x - 5)

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Solution

The correct option is A $(x + 5) (x - 1)$
$P (x) = x^{2} + 4 x - 5$
$\Rightarrow P (x) = x^{2} + 5 x - x - 5$
$\Rightarrow P (x) = x (x + 5) - 1 (x + 5)$
$\Rightarrow P (x) = (x + 5) (x - 1)$

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Factors of

$- x^{3} - 125$

Verify whether the following are zeroes of the polynomial, indicated against them.
(i) p(x)=3x+1,x= $\frac{- 1}{3}$

(ii) p(x)=5x− $π$ ,x= $\frac{4}{5}$

(iii) p(x)= $x^{2}$ -1,x=1,−1

(iv) p(x)=(x+1)(x−2),x=−1,2

(v) p(x)= $x^{2}$ ,x=0

P (x) = x^{2} + 4 x - 5

\frac{1}{x - 1} - \frac{1}{x + 5} = \frac{6}{7}, x \neq 1, - 5

4 x^{3} + x^{2} + 5 x + 8

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