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Question

The father’s age is six times his son’s age. Four years from now, the age of the father will be four times his son’s age. The present ages (in years) of the father and the son respectively are ___.

A
36 years, 6 years
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B
60 years, 10 years
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C
30 years, 5 years
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D
24 years, 4 years
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Solution

The correct option is A 36 years, 6 years
Let x years and y years represent the ages of the father and the son respectively. Then, we have x=6y ...(1)
Four years from now, the father's age will be x+4 years and the son's age will be y+4 years.
Thus, we have x+4=4(y+4)
x4y=12 ...(2)
Substituting the value of x from (1) in (2), we have
6y4y=122y=12y=6.
Since x=6y, we have x=36.
Hence, the present ages of the father and the son are 36 years and 6 years respectively.

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