The fault current in kA for a 100 MVA- 132 kV system- When 3 - - fault current is - j5 p-u- is Given answer upto 3 decimals-

Fault current (kA) = Base current × Fault current (p.u.) Base current =MVA/√(3)× KV× 1000 A =100/√(3)× 132× 1000 = 437.4 A Fault current =437.4 × 5 = ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Motional EMF

The fault cur...

Question

The fault current in kA for a 100 MVA; 132 kV system. When $3 - ϕ$ fault current is - j5 p.u. is ________(Given answer upto 3 decimals).
2.187

Open in App

Solution

The correct option is A 2.187
$F a u l t c u r r e n t (k A) = B a s e c u r r e n t \times F a u l t c u r r e n t (p . u .)$

$B a s e c u r r e n t = \frac{M V A}{\sqrt{3} \times K V} \times 1000 A = \frac{100}{\sqrt{3} \times 132} \times 1000 = 437.4 A$

$F a u l t c u r r e n t = 437.4 \times 5 = 2.187 k A$

Suggest Corrections

Similar questions

Q. For a power system:

L i n e t o l i n e f a u l t c u r r e n t = - j 2.5 p . u .

3 - ϕ f a u l t c u r r e n t = - j 5 p . u .

The positive and negative sequence reactances are

Q. Three 6.6 kV, 3-

ϕ

, 10 MVA alternators are connected to a common bus. Each alternator has a positive negative and zero sequence reactances as 0.15 p.u., 0.1 p.u.,0.05 p.u. respectively. A single line to ground fault occurs at point F, as shown in figure below.

I_{f}

is the fault current when all the alternator neutrals solidy grouned

I_{f}^{'}

is the fault current when only one neutral is solidly grounded and other two neutrals are isolated. Then the value of

| I_{f} - I_{f}^{'} | =

________kA.

Q. A 3-phase power system is represented by one line diagram as shown in the figure below:

The ratings of equipments are the following:
Genrator (G) : 15 MVA, 6.6 kV,

X_{1}

= 15%,

X_{2}

= 10%
Transformer : 15 MVA, 6.6 kV delta/33 kV star,

X_{1} = X_{2} = X_{0} = 6

%
Line reactance :

X_{1} = X_{2} = 2 Ω a n d X_{0} = 6 Ω

If a SLG fault occurs on bus bar B, then the fault current is _______ p.u.

Q. The

Z_{b u s}

of a system is

Z_{B U S} = ⎡ ⎢ ⎣ \begin{matrix} 0.1 & 0.1 & 0.1 0.1 & 0.2 & 0.1 0.1 & 0.1 & 0.3 \end{matrix} ⎤ ⎥ ⎦ p . u

If a 3 phase fault occurs at BUS-2, the p.u. fault current in each phase is -

Q. A 25 MVA, 13.2 kV alternator with solidly grounded netural has a substransient reactance of 0.25 p.u. The negative and zero sequence reactance are 0.35 and 0.1 p.u. respectively. A single line to ground fault occurs at the terminals of an unloaded alternator, then the fault current is

Join BYJU'S Learning Program

The fault current in kA for a 100 MVA; 132 kV system. When 3−ϕ fault current is - j5 p.u. is ________(Given answer upto 3 decimals).2.187

The correct option is A 2.187Fault current (kA) = Base current × Fault current (p.u.) Base current =MVA√3×KV×1000 A=100√3×132×1000=437.4 A Fault current=437.4×5=2.187 kA

The fault current in kA for a 100 MVA; 132 kV system. When $3 - ϕ$ fault current is - j5 p.u. is ________(Given answer upto 3 decimals).
2.187