The figure below shows an aero plane of mass 3.4 × 10^5kg accelerating uniformly from rest along a runway. After 26 s it reaches a speed of 65 m/s.Calculate the resultant force on the aero plane.

Open in App

Solution

Dear student,

Acceleration = change in velocity / Time
= v- u/ t
v is the final velocity,
u is the initial velocity
t s the time taken
a = 65m s^-1 - 0 / 26s
= 65 / 26 = 2.5 m s^-2

Force = mass x accelaration
Mass = 3.4 x 10⁵ kg
Force = 3.4 x 10⁵ Kg x 2.5 ms^-2
= 8.5 x 10⁶ N

The resultant force is 8.5 x 10⁶ N
Regards

Suggest Corrections

Similar questions

Q. An aeroplane requires a speed of

108

k m p h

to take off, to achieve that plane runs on the runway of

100

m

. Mass of the plane is

10400

k g

and the coefficient of friction between the plane and the ground is

0.2

. Assuming the plane accelerates uniformly, the minimum force required is (Take

g = 9.81 m / s^{2}

)

An aero-plane takes 1 hr less for a journey of 1200 km. If its speed is increased by 60 km/hr from the initial speed. Find the initial speed of the plane.

Q. An aeroplane of mass

M

requires a speed

v

for take-off. The length of runway is

s

and the coefficient of friction between the tyres and the ground is

μ

. Assuming that the plane accelerates uniformly during the take-off, the minimum force required by the engine of the plane for take-off is

An object of mass 100kg is accelerated uniformly from a velocity of 5m/s to 8m/s in 6s.Calculate the initial and final momentum of the object.Also,find the magnitude of the force exerted on the object.

Q. An engineer is designing the runway for an airport of the planes that will use the airport, the lowest acceleration rate is likely to be

3 m / s^{2}

. The takeoff speed for this plane will be

65 m / s

. Assuming this minimum acceleration, what is the minimum allowed length for the runway? (in m)

Join BYJU'S Learning Program