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Relative Velocity

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Question

The figure represented the velocity-time graph of body moving in a straight line. How much distance does it travel during the last $10$ seconds?

A

40 m

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B

80 m

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C

100 m

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D

220 m

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Solution

The correct option is C $100 m$
Distance is $d = v e l o c i t y \times t i m e$ which is nothing but $a r e a$ under the curve between the limits $t = 10 s$ to $t = 20 s$
so area of this triangle is $\frac{b a s e \times h e i g h t}{2} = \frac{(20 - 10) s \times 20 m / s}{2} = 100 m$
Option C is correct.

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