The figure shows graph between stopping potential along y-axis and incident frequency along x-axis for different target metal A- B- C and D- Let - A- B- C and - Dare the work function of different target metals A- B- C and D respectively Then the correct rank of work function of different target metals is

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Stopping Potential vs Frequency

The figure sh...

Question

The figure shows graph between stopping potential (along $y$ -axis) and incident frequency (along x-axis) for different target metal $A, B, C$ and $D$ . Let $ϕ_{A}, ϕ_{B}, ϕ_{C} a n d ϕ_{D}$ are the work function of different target metals $A, B, C$ and $D$ respectively Then the correct rank of work function of different target metals is

ϕ_{A} > ϕ_{B} > ϕ_{C} > ϕ_{D}

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ϕ_{A} < ϕ_{B} < ϕ_{C} < ϕ_{D}

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ϕ_{A} = ϕ_{B} = ϕ_{C} = ϕ_{D}

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can not be predict from the given data

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Solution

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f (x) = \frac{1}{\sqrt{| x | - x}}

g (x) = \frac{1}{\sqrt{x - | x |}}

\frac{1}{λ}

(V)

ϕ_{1}

ϕ_{2}

ϕ_{3}

λ

ϕ_{1} : ϕ_{2} : ϕ_{3} = 1 : 2 : 4

ϕ_{1} : ϕ_{2} : ϕ_{3} = 4 : 2 : 1

tan θ \propto \frac{h c}{e}

h =

c =

\frac{d y}{d x} = \frac{y}{x} + \frac{ϕ (\frac{y}{x})}{ϕ' (\frac{y}{x})}

ϕ (\frac{y}{x}) = k x

x ϕ (\frac{y}{x}) = k

ϕ (\frac{y}{x}) = k y

y ϕ (\frac{y}{x}) = k

V_{0}

f

|x|

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